Question

What is the unit digit in (384)1793 x (1035)317 x (261)491?✌☺❤​

Answer 1

Answer:

Any Number that ends with 4 when multiplied by itself would have any one of these two numbers at the last digit: 1. 4, when multiplied by ...

Missing: ✌ ‎☺ ‎❤

Answer 2

Answer:

okay fine..

answer of your question is given below

Step-by-step explanation:

Any Number that ends with 4 when multiplied by itself would have any one of these two numbers at the last digit:

4, when multiplied by itself odd number of times: (….4)^(2n+1)=(….4).

6, when multiplied by itself even number of times: (….4)^2n=(….6).

Any number that ends with 5 when multiplied by itself any number of times would have 5 as its last digit: (….5)^n=(….5).

Any number that ends with 1 when multiplied by itself any number of times would have 1 as its last digit: (….1)^n=(….1).

So,

[(6374)^1793] would have 4 as its last digit. Let it be [….4].

[(625)^317] would have 5 as its last digit. Let it be [….5].

[(341)^491] would have 1 as its last digit. Let it be [….1].

Now, when some number that ends with 5 is multiplied with a number that ends with 4, its last digit would be 0. So, [(6374)^1793]x[(625)^317]={….0}.

And when any number is multiplied with a number that ends in 0 will as well have 0 as its last digit.

So, the units digit of [(6374)^1793]x[(625)^317]x[(341)^491] would be 0.

P.S. I don’t consider 0 as an acceptable exponent in regard to answering this question.