What is the unit digit in the product (3)^{166} + (5)^{159}?
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Answered by
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Answer:
5469
Step-by-step explanation:
3^2 * 166 + 5^2 * 159
9 * 166 + 25 * 159
= 5469
Answered by
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- Any number to the power 5 will have its unit digit as 5.
- Observing the powers of 3, we see :3¹=3(3ⁿ⁺¹)
3²=9(3ⁿ⁺²)
3³=27(3ⁿ⁺³)
3⁴=81(3ⁿ⁺⁴)
3⁵=243 (3ⁿ⁺¹)
- The unit place of powers of 3 repeat after every 4 numbers.
- 166 divided by 4 gives remainder as 2 so it is of form 3²=9(3ⁿ⁺²), ∴ unit place will be 9.
- 3¹⁶⁶(unit place)=9 and 5¹⁵⁹(unit place)=5.
- 9+5=14, unit digit =4.
- ∴Unit digit of the product=4
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