what is the unit's place after expanding (756)⁹⁹⁹
Answers
Answer:
The Cyclicity table for 7 is as follows:
71 =7
72 =49
73 = 343
74 = 2401
Let’s divide 295 by 4 and the remainder is 3.
Thus, the last digit of 7295 is equal to the last digit of 73 i.e. 3.
The Cyclicity table for 3 is as follows:
31 =3
32 =9
33 = 27
34 = 81
35 = 243
Let’s divide 158 by 4, the remainder is 2. Hence the last digit will be 9.
Therefore, unit’s digit of (7925 X 3158) is unit’s digit of product of digit at unit’s place of 7925 and 3158 = 3 * 9 = 27. Hence option 1 is the answer.
Step-by-step explanation:
The Cyclicity table for 7 is as follows:
71 =7
72 =49
73 = 343
74 = 2401
Let’s divide 295 by 4 and the remainder is 3.
Thus, the last digit of 7295 is equal to the last digit of 73 i.e. 3.
The Cyclicity table for 3 is as follows:
31 =3
32 =9
33 = 27
34 = 81
35 = 243
Let’s divide 158 by 4, the remainder is 2. Hence the last digit will be 9.
Therefore, unit’s digit of (7925 X 3158) is unit’s digit of product of digit at unit’s place of 7925 and 3158 = 3 * 9 = 27. Hence option 1 is the answer
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