Question

what is the unit vector perpendicular to the following vectors 2i+2j-k and 6i-3j+2k​

Answer 1

Explanation:

→A=2i+2j-k,→B=6i-3j+2k →A×→B= |Ijk22-16-32|=i-10j-18k |→A×→B|=√(1)2+(-10) 2+(-18)2=√425=5√17