Science, asked by hudaassaf, 1 year ago

what is the use of 1.2 % NA CL solutions

Answers

Answered by sohil88
0

Explanation:

The thing to remember about dilution calculations is that the dilution factor,

DF

, can be calculated by taking

The ratio that exists between the concentration of the stock solution and the concentration of the diluted solution

The ratio that exists between the volume of the diluted solution and the volume of the stock solution

So for any dilution, you have

DF

=

concentration ratio: stock/diluted



c

stock

c

diluted

=

volume ratio: diluted/stock



V

diluted

V

stock

In your case, the dilution factor is equal to

DF

=

1.2

M

0.12

M

=

10

This tells you that the volume of the diluted solution is

10

times the volume of the stock solution.

You can thus say that you have

V

stock

=

V

diluted

DF

which, in your case, will get you

V

stock

=

1 L

10

=

0.1 L

−−−−−

The answer is rounded to one significant figure.

So, in order to perform this dilution, you take

0.1 L

of a

1.2-M

stock solution of sodium chloride and add enough water to get the final volume of the solution to

1 L

.

This will decrease the concentration of sodium chloride from

1.2 M

in the stock solution to

0.12 M

in the diluted solution.

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