Question

What is the valency of C in CCl4?​

Answer 1

$\fcolorbox{red}{aqu}{Answer:}$

+4

Valency of Carbon in CCl4 is +4. Because the valency of Cl is -1 and to nutralize (-1×4) = -4, the carbon atom is needed to be in +4 state......♡

Answer 2

$</p><p> </p><p> <div style="</p><p> margin:20px auto;</p><p> width:90%;</p><p> padding:50px 5px;</p><p> text-align: center;</p><p> font-family:Monoscape;</p><p> background-image: radial-gradient(circle at center center, rgba(217, 217, 217,0.05) 0%, rgba(217, 217, 217,0.05) 15%,rgba(197, 197, 197,0.05) 15%, rgba(197, 197, 197,0.05) 34%,rgba(178, 178, 178,0.05) 34%, rgba(178, 178, 178,0.05) 51%,rgba(237, 237, 237,0.05) 51%, rgba(237, 237, 237,0.05) 75%,rgba(138, 138, 138,0.05) 75%, rgba(138, 138, 138,0.05) 89%,rgba(158, 158, 158,0.05) 89%, rgba(158, 158, 158,0.05) 100%),radial-gradient(circle at center center, rgb(255,255,255) 0%, rgb(255,255,255) 6%,rgb(255,255,255) 6%, rgb(255,255,255) 12%,rgb(255,255,255) 12%, rgb(255,255,255) 31%,rgb(255,255,255) 31%, rgb(255,255,255) 92%,rgb(255,255,255) 92%, rgb(255,255,255) 97%,rgb(255,255,255) 97%, rgb(255,255,255) 100%); background-size: 42px 42px;</p><p> box-shadow:0 20px 30px 0px rgba(0,0,0,.5),</p><p> 0 6px 6px 0px rgba(0,0,.14),</p><p> 0 4px 4px 0px rgba(0,0,.1);</p><p> border-radius:1%;</p><p> "></p><p> </p><p> <span style="text-align: center; border-bottom:2px double #9654fe; color: #9654fe; ">Solution To Your Question &#x2193;</span> </p><p> </p><p> <p style="color: #000;</p><p> text-shadow:0px 0px 10px rgb(245,242,242);</p><p> text-align: center;</p><p> font-weight: 400; "></p><p> </p><p> </p><p><b><em><u>+4</u></em></b></p><p> </p><p>Valency of Carbon in CCl4 is +4. Because the valency of Cl is -1 and to nutralize (-1×4) = -4, the carbon atom is needed to be in +4 state.</p><p> </p><p> &#128513; Hope You Liked It &#128513;</p><p> </p></p><p> </p><p> </p><p> <marquee style="color:#000;"> <b>Mark Me as the brainliest and Follow Me &#128151;</p><p> </p><p> </b></marquee></p><p> </p><p> </p><p> </p><p> </div></p><p> </p><p> </p><p>$