Question

what is the value a3-b3/a2+ab+b2=?​

Answer 1

Answer:

hope i helped you

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Step-by-step explanation:

(a^3+b^3)/(a^2-ab+b^2).

(a^3+b^3) can be factorized as (a+b)(a^2-ab+b^2).

Hence, (a^3+b^3)/(a^2-ab+b^2)

= (a+b)(a^2-ab+b^2)/(a^2-ab+b^2)

= (a+b). Answer

Answer 2

Let the given equation be 'x' then

$x = \frac{a^3-b^3}{a^2+ab+b^2} ---- > (1)$

we can write $a^3-b^3 = (a-b)*(a^2+ab+b^2)$

now by substituting the above value in $(1)$ we get

$x = \frac{(a-b)*(a^2+ab+b^2)}{a^2+ab+b^2}$

by cancelling the common terms we get

$x = (a-b)$

∴The value of $\frac{(a^3-b^3)}{a^2+ab+b^2} = (a-b)$

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