Math, asked by crazimathx, 10 months ago

what is the value for
cos^{-1}(x)*cos^{-1}(1/x)
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Answers

Answered by bhanuprakashreddy23
5

Answer:

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Step-by-step explanation:

=cos^{-1}(x)×cos^{-1}(1/x)

=cos^{-1}(x)×sec^{-1}(x). (cos^{-1}(1/x)=sec^{-1(x))

=1/cos(x)×cos(x). (cos^{-1}(x)=1/cos(x))

=1. (sec^{-1(x)=cos(x))

Answered by amiteshkumar71
1

Answer:

= cos ^{-1}(x)× cos^{-1}(1/x)

=cos^{-1}(x)×sec^{-1}(x) (cos^(-1)(1/

X) =sec^{-1(x)}

=1/cos (x)×cos (x). (cos^(-1)(x)=1/

Cos(x)

= 1. (sec^(-1(x)=cos(x)

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