what is the value of (-1)×(-1)×(-1)×...2m times where m is a natural number
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the value of the value of (-1)×(-1)×(-1)×...2m times where m is a natural number will always be 1.
(-1)×(-1)×(-1)×... will be (-1)²m
As in any case 2m will be even
Therefore, value will come out to be 1.
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Step-by-step explanation:
=(-1)×(-1)×(-1)×2m
=(-1)×(-1)×(-1) = -1 × 2m.. -1×2m = -2m
Hope It helps you
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