Question

what is the value of 1+cos2x​

Answer 1

$\huge\mathfrak\red{ANSWER}$

Since, cos2x=cos2x−sin2x

Since, cos2x=cos2x−sin2x 1−cos2x=1−(cos2x−sin2x)

Since, cos2x=cos2x−sin2x 1−cos2x=1−(cos2x−sin2x) 1−cos2x=1−cos2x+sin2x

Since, cos2x=cos2x−sin2x 1−cos2x=1−(cos2x−sin2x) 1−cos2x=1−cos2x+sin2x We know,

Since, cos2x=cos2x−sin2x 1−cos2x=1−(cos2x−sin2x) 1−cos2x=1−cos2x+sin2x We know,sin2x+cos2x=1

Since, cos2x=cos2x−sin2x 1−cos2x=1−(cos2x−sin2x) 1−cos2x=1−cos2x+sin2x We know,sin2x+cos2x=1 Therefore, sin2x=1−cos2x

Since, cos2x=cos2x−sin2x 1−cos2x=1−(cos2x−sin2x) 1−cos2x=1−cos2x+sin2x We know,sin2x+cos2x=1 Therefore, sin2x=1−cos2x Substituting it in 1−cos2x , we get,

Since, cos2x=cos2x−sin2x 1−cos2x=1−(cos2x−sin2x) 1−cos2x=1−cos2x+sin2x We know,sin2x+cos2x=1 Therefore, sin2x=1−cos2x Substituting it in 1−cos2x , we get,1−cos2x=sin2x+sin2x

Since, cos2x=cos2x−sin2x 1−cos2x=1−(cos2x−sin2x) 1−cos2x=1−cos2x+sin2x We know,sin2x+cos2x=1 Therefore, sin2x=1−cos2x Substituting it in 1−cos2x , we get,1−cos2x=sin2x+sin2x 1−cos2x=2sin2x

Answer 2

Answer:

using formula

1+cos2x = 2cos²x