Question

What is the value of (1 + cot
A)2 + (1 -­ cot

Answer 1

Answer:

$\huge\boxed{ {cosec}^{2} A}$

Step-by-step explanation:

$cotA = \frac{base}{perpendicular} \\ = \frac{b}{p}$

$(1 + cotA)(1 + cotA) = 1 + {cot)}^{2} A$

$1 + {cot}^{2} A \\ = 1 + \frac{b}{p} \\ = \frac{ {b}^{2} + {p}^{2} }{ {p}^{2} } \\ = \frac{ {h}^{2} }{ {p}^{2} } \\ = {cosec}^{2}A$

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