Question

what is the value of : 1..current flow of current through 6 ohm resistor


answer plezz​

Answer 1

Given:-

• Resistance of Resistor ,R1 = 6Ω

• Resistance of Resistor ,R2 = 3 Ω

• Potential Difference ,V = 4v

To Find:-

• Current flow through 6 ohm resistor .

Solution:-

As the given figure we observe that the two Resistors 6 ohm & 3 ohm are connected in series . So firstly we calculate the equivalent Resistance in this connection/combination.

• Req = R1 + R2 + ...

Where,

Req is the equivalent resistance of Resistors

R1 is the Resistance of 1st Resistor

R2 is the Resistance of 2nd Resistor

Substitute the value we get

→ Req = 6 Ω + 3Ω

→Req = 9Ω

Now, Applying Ohm's Law in the given combination

• V = IR

Where,

V is the Potential Difference

I is the Current

R is the Resistance (Equivalent Resistance)

Substitute the value we get

→ 4 = I × 9

→ I = 4/9 A

We know that the current in the series combination is same everywhere . Therefore, the current through the 6 ohm resistor is 4/9 Ampere .

Answer 2

Answer :-

• Current in 6$Ω$ resistor = $\boxed{\tt{\red{\dfrac{4}{9}\:A}}}$

To find :-

• Current in 6$Ω$ resistor.

Points to remember :-

• In parallel connection,

Voltage (V) is constant.

• In series connection,

Current (I) is constant.

Solution :-

• Blue wire splits into red and orange wire in parallel connection.

So, wire red has Voltage (V) = 4V (constant)

• Let Current in red wire = I

Resistance in red wire = 6 + 3 = 9$Ω$

In red wire,

V = IR ⇒ 4 = I × 9 ⇒ I = 4/9 A

• We know that,

In red wire, resistors are in series.

So, Current is constant.

∴ Current in 6$Ω$ resistor = 4/9 A