what is the value of 1/(x-y) -{1/(x+y)}
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Answered by
1
{1/(x-y)-1/(x+y)}= {(x+y)-(x-y)/(x-y)(x+y)}
=x+y-x+y/x^2-xy+xy-y^2
=2y/x^2-y^2
=x+y-x+y/x^2-xy+xy-y^2
=2y/x^2-y^2
Answered by
2
Heya,
Here is the solution:-
1/(x-y) -{1/(x+y)}
= 1/(x-y) - 1 / (x+y)
= x+y -x+y/ x^2 - y^2
= 2y/ x^2 - y^2.
Hope it helps u...
Here is the solution:-
1/(x-y) -{1/(x+y)}
= 1/(x-y) - 1 / (x+y)
= x+y -x+y/ x^2 - y^2
= 2y/ x^2 - y^2.
Hope it helps u...
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