Question

What is the value of (12+1)1!+(22+1)2!+...+(20202+1)2020!?

Answer 1

Hi buddy

Here is your answer

12 +1=13

13*1=13

13 +(22 +1)2

13+(23)2

13 +46

=59

59 +(20202+1)

59+(20203)2020.

59+40810060

=408100119

Hope it help you

Please mark me please

#sibi ❤️

Answer 2

Answer:

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Step-by-step explanation:

(12+1)1!+(22+1)2!+...+(20202+1)2020

》12×1+1×1 + 22×2+2×2+ 2020×2020+1×2020

》12+1+44+4+4,080,400+2020

》4,082,481