Question

what is the value of (17 - x) whole square

Answer 1

(17-x)²
= 289+x²-34x

so 289+x²-34x is the value of (17-x)²

Answer 2

(a-b)^2 = a^2 - 2ab + b^2......formula (17-x)^2 = 17^2 - 2*17*x + x^2              = 289 - 34x + x^2 Now factorise the equation,  x^2 - 34x + 289