what is the value of (17 - x) whole square
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(17-x)²
= 289+x²-34x
so 289+x²-34x is the value of (17-x)²
= 289+x²-34x
so 289+x²-34x is the value of (17-x)²
pranati18:
could you please explain step by step......
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(a-b)^2 = a^2 - 2ab + b^2......formula (17-x)^2 = 17^2 - 2*17*x + x^2 = 289 - 34x + x^2 Now factorise the equation, x^2 - 34x + 289
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