what is the value of √2-3i
tell me the simplest way to solve it
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there is nothing called as the value of a complex number. but there is something called the absolute value of a complex number which is actually the distance of the complex number from the origin in the argand plane. the absolute value of a complex number is:-
![|a+ib|= \sqrt{a^2+b^2} |a+ib|= \sqrt{a^2+b^2}](https://tex.z-dn.net/?f=%7Ca%2Bib%7C%3D+%5Csqrt%7Ba%5E2%2Bb%5E2%7D+)
therefore
therefore
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absolute value of 2^1/2-3i=(2^1/2^2+(-3)^2) (since,abs. value of a+bi=(a^2+b^2))
=(2+9)^1/2=11^1/2
=(2+9)^1/2=11^1/2
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