Question

what is the value of ?:- 2cos²thita (1 +tan² thita)​

Answer 1

Answer:

2

Step-by-step explanation:

cos^2A = 1 / Sec^2A

or ( 1 + tan^2A = Sec^2A )

: 2 × 1/Sec^2A ( sec^2A )

= 2 ( 1 / sec^2A × sec^2 = 1 )

Answer 2

Step-by-step explanation:

2Cos²∅(1+tan ²∅)

2cos²∅(sec²∅)

2*1

2