Question

what is the value of (3^3*81^2*2^0)/9^5?
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Answer 1

Answer:

3

Step-by-step explanation:

(3^3 * (9^2)^2 * 1)/(3^2)^5

(3^3 * (3^2)^4)/3^10

(3^3 * 3^8)/3^10

3^11/3^10

3

Answer 2

Answer:

Required value of the given term is 3.

Step-by-step explanation:

Given,

$\frac{ {3}^{3} \times {81}^{2} \times {2}^{0} }{ {9}^{5} } \\ = \frac{ {3}^{3} \times {3}^{ {4}^{2} } \times 1 }{ { {3}^{2} }^{5} } \\ = \frac{ {3}^{3} \times {3}^{4 \times 2} \times 1 }{ {3}^{2 \times 5} } \\ = \frac{ {3}^{3} \times {3}^{8} }{ {3}^{10} } \\ = \frac{ {3}^{3 + 8} }{ {3}^{10} } \\ = \frac{ {3}^{11} }{ {3}^{10} } \\ = {3}^{11 - 10} \\ = {3}^{1} \\ = 3$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549