Question

what is the value of 6.67×10^-11×40×80÷2^2​

Answer 1

Given : m
1
​
=80 kg m
2
​
=1200 kg d=10 m
Force of gravitation F=
d
2

Gm
1
​
m
2
​

​

Or F=
10
2

6.67×10
−11
×80×1200
​
=6.4×10
−8
N

Answer 2

$6.67 \times {10}^{ - 11} \times 40 \times 80 \div 2 {}^{2}$

$(6.67 \times {10}^{ - 11} ) (40 \times 80) \div {2}^{2}$

$\: \:0.00000000007 \: (40 \times 80) \div {2}^{2}$

$0.00000000007 \times 3200 \div {2}^{2}$

$0.000000224 \div {2}^{2}$

$0.000000224 \div 4$

$0.000000056 \: is \: ur \: answer$