Question

What is the value of(6° -2°) (6° +2°)​

Answer 1

Answer:

when we open the braket then we have to multiply the numbers or digit

Answer 2

Answer:

The value of

$\sf\:(\:6^{0}\:-\:2^{0}\:)\:(\:6^{0}\:+\:2^{0}\:)$ is 1.

Step-by-step explanation:

$\sf\:(\:{6}^{0} - {2}^{0}\:)\:({6}^{0}\ + {2}^{0}\:)\\\\\longrightarrow\sf\:( \: {4}^{0} \: )\:\times\:( \:{8}^{0} \: )\\\\\longrightarrow\sf\:{32}^{0}\\\\\longrightarrow\sf\:1$

Here, we have to use the rule of indices

$\sf\:a^{0}\:=\:1$

Hence, the value of any number raised to zero is 1. And the product of 1 × 1 is always 1.

Some rules of indices:

$\sf\:1.\:a^{m}\:\times\:b^{m}\:=\:a^{m\:+\:n}\\\\\sf\:2.\:a^{m}\:\div\:b^{m}\:=\:a^{m\:-\:n}\\\\\sf\:3.\:(\:a^{m}\:)^{n}\:=\:a^{m\:\times\:n}\\\\\sf\:4.\:a^{0}\:=\:1$