Question

what is the value of -6x²+(-x²/2)

Answer 1

Hello mate...✔✔✔

Given......

$- 6x {}^{2} + ( - \frac{ x {}^{2} }{2} )$

$- 6x {}^{2} - \frac{x {}^{2} }{2}$

$\frac{ 2( - 6x {}^{2} ) - x {}^{2} }{2}$

$\frac{ - 12x {}^{2} - x {}^{2} }{2}$

$= > \frac{ - 13x {}^{2} }{2}$

Hope it helps you dear.....✔✔✔

Answer 2

We have,

• To find the value obtained on addition of $\rm { - 6x}^{2}$ and $\rm \frac{ { - x}^{2} }{2}$.

So,

$\large \boxed{ \dag} \: \: \: \: \: \rm { - 6x}^{2} + \frac{ { - x}^{2} }{2} \\ \\ \sf\mapsto \: \: \frac{2( { - 6x}^{2} ) + {( - x)}^{2} }{2} \\ \\ \sf\mapsto \: \: \frac{ { - 12x}^{2} - {x}^{2} }{2} \: \: \: = \boxed{ \bf \frac{ { - 13x}^{2} }{2} }$

Hence,

• Required Sum is $\rm \frac{ { - 13x}^{2} }{2}$.