what is the value of √(7-4√3)
Answers
Step-by-step explanation:
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√)
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3)
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√)
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]=2−3–√4–3
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]=2−3–√4–3 =2+3–√
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]=2−3–√4–3 =2+3–√ So 1/x=2−3–√
I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]=2−3–√4–3 =2+3–√ So 1/x=2−3–√ So x+1x=(2+3–√)+(2−3–√)=4
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