Question

what is the value of √(7-4√3)​

Answer 1

Step-by-step explanation:

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√)

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3)

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√)

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]=2−3–√4–3

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]=2−3–√4–3 =2+3–√

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]=2−3–√4–3 =2+3–√ So 1/x=2−3–√

I think the question is x=(√7+43–√) not 7–√+43–√ ( if so , then already answer is given)So,x=(√7+43–√) Now7+4(√3)=22+2∗2∗3–√+(3–√)2 =(2+3–√)2 Hence 7+43–√−−−−−−−√ = 2 +3–√ So x=2+(√3) 1/x=1(2+3–√) =2−3–√22−3–√2 [ multiplying numerator and denominator by 2+(√3) ]=2−3–√4–3 =2+3–√ So 1/x=2−3–√ So x+1x=(2+3–√)+(2−3–√)=4

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