Question

What is the value of (a-1) (a+1) (a square +1)

Answer 1

Answer:

(a-1) ( a+1) (a^2+1) = ? , (a-1) (a+1) is in the form of (a+b) (a-b)= a^2-b^2, i.e (a-1) (a+1)= a^2-1 , (a+1) (a-1) (a^2+1)= (a^2-1)(a^2+1) which is again in the form of (a+b)(a-b)= a^2-b^2, i.e (a^2-1)(a^2+1)= a^4-1. Hence the final answer is a^4-1. Hope this helps you.

Answer 2

Step-by-step explanation:

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