Math, asked by amolkchand945, 1 month ago

What is the value of (a^8×a^-5)^0​

Answers

Answered by shreekrishna35pdv8u8
1

Step-by-step explanation:

(a^8×a^-5)^0 \\  = a {}^{8 \times 0}  \times  {a}^{ - 5 \times 0}  \\  = a {}^{0}  \times  {a}^{0} \\   = 1 \times 1 \\  = 1

Answered by drnupurdas
0

Answer:

SO THE ANSWER IS 1

Step-by-step explanation:

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