Math, asked by sanjeev7841, 10 months ago

what is the value of (a+b)^2-(a-b)^2​

Answers

Answered by unknown178
1

Answer:

4ab

Step-by-step explanation:

(a+b)^2-(a-b)^2

(a^2+b^2+2ab)-(a^2+b^2-2ab)

a^2+b^2+2ab-a^2-b^2+2ab

4ab

Answered by Anonymous
0

QUESTION:

what is the value of (a+b)^2-(a-b)^2

ANSWER:

We use the identity here;

 {x}^{2}  -  {y}^{2}

the expansion of the identity is;

(x + y)(x - y)

now come to main question;

let

(a + b) = x \\  \\ ( a - b) = y

so,

( {a + b})^{2}  - ( {a - b})^{2}

(a + b + a - b)(a + b - a + b) \\ 2a + 2b \\ (taking \: two \: common) \\ 2(a + b)

FINAL ANSWER :

\huge\red{2(a + b)}

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