Math, asked by parthahazarika65, 10 months ago

What is the value of (a^b-b^a) if a = 2 and b =(-3)​

Answers

Answered by yash12384
1

Answer:

 ({a}^{b}  -  {b}^{a} )

( {2}^{ - 3}  +  {3}^{2} )

(  \frac{1}{ {2}^{3} }  +  {3}^{2} )

( \frac{1}{8}  + 9)

 \frac{73}{8}

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Answered by iopenattheclose934
0

Answer:

-71/8

Step-by-step explanation:

(a^b-b^a) where a=2 and b=-3

On substituting:

2^-3 - (-3)^2

1/2^3 -9

1/8 -9

On taking LCM

1/8-72/8

-71/8

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