Question

What is the value of a + b , if the quadrilateral is a parallelogram?
18 cm
b- 10
15 cm
a -
a - 2b​

Answer 1

Answer:

As the diagonal of quadrilateral bisects each other; 5b-4=3b+6

2b=10

b=5

So by the same rule;3b-4=2a

15-4=2a

11=2a

a=

2

11

Answer 2

Given:

The quadrilateral is a parallelogram.

Opposite sides are: (5a-13) and (3a-5), 8b and 10b-3.

To find:

a+b

Method of solving:

The opposite sides of a parallelogram are equal.

Step-by-step explanation:

Step 1 of 2

The opposite sides a parallelogram are equal so,

AB = CD   and    BC = DA

$5a -13 = 3a - 5\\\\5a-3a=-5+13\\\\2a=8\\\\a=4$

$8b=10b-3\\\\10b-8b=3\\\\2b=3\\\\b=\frac{3}{2}$

Step 2 of 2

So, a + b will be

$4+\frac{3}{2} =\frac{8+3}{2} =\frac{11}{2}$

a+b = 11/2