Question

what is the value of a in the A.P
2a,a+10 and 3a+2

Answer 1

Answer:

Step-by-step explanation:

Given, a, (a - 2) and 3a are in AP Hence a2 - a1 = a3 - a2 ⇒ (a - 2) - a = 3a - (a - 2) ⇒ a - 2 - a = 3a - a + 2 ⇒ - 2 = 2a + 2 ⇒ - 4 = 2a ∴ a = - 2

Answer 2

A =6
As, (a+10) - (2a) = (3a+2) - (a+10)
:., - a + 10 = 2a - 8
3a = 18
a= 6

Or

2b=a+c
2a+20= 2a + 3a +2
2a+20= 5a + 2
18=3a
A=6

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