Question

what is the value of a0, if f(x) =X³ in the interval 0 to 5​

Answer 1

Find,integration of (limit 0 to 5) f(X)=x^3

=625/256

Answer 2

Given : f(x) =X³, in the interval 0 to 5​

$\int\limits^5_0 {x^3} dx=[\frac{x ^{3+1} }{3+1}]{{5} \atop {0}} \right.$

$=[\frac{x ^{4}}{4}]{{5} \atop {0}} \right.$

$=\frac{1}{4}[5 ^{4}-0^{4}]$

$=\frac{5 ^{4}}{4}$

$=\frac{625}{4}$