Question

What is the value of a² + b² + c ?

if - 3a + 3b + 2c = 34 and 2a + 5b + 6c = 72​

Answer 1

Answer:

If a+2b+3c=4, then what is the minimum value of a2+b2+c2a2+b2+c2?

00000000000000000000000000000000000000000000

We can put the relation as

(ai^+bj^+ck^).(i^+2j^+3k^)=4(ai^+bj^+ck^).(i^+2j^+3k^)=4

a2+b2+c2−−−−−−−−−−√12+22+32−−−−−−−−−−√cosθ=4a2+b2+c212+22+32cos⁡θ=4

a2+b2+c2=4214cos2θa2+b2+c2=4214cos2⁡θ

maximum value of cos2θ=1⟹cos2⁡θ=1⟹

Minimum value of a2+b2+c2=87

Step-by-step explanation:

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