what is the value of ab+bc+ca-a²-b²+c², if a=2, b=3 and c=(-3) ?
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Answered by
0
Answer:
ANSWER
We know that
(a+b+c)
2
=a
2
+b
2
+c
2
+2(ab+bc+ca)
Given ab+bc+ca=q
a+b+c=p
=>p
2
=a
2
+b
2
+c
2
+2(q)
=>a
2
+b
2
+c
2
=p
2
−2q
Answered by
0
Step-by-step explanation:
- 2*3 + 3*(-3) + (-3)*2 - 2*2 - 3*2
- 6 + 3*(-3) + (-3)*2 - 2*2 -3*2
- 9*(-3) +(-3)*2 - 2*2 - 3*2
- 27 + (-3) * 2 - 2*2 -3*2
- -24*2 - 2*2 - 3*2
- -48 - 4 - 6
- -38 :- This is your answer...
Hope you understand please mark me brain liest
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