Question

what is the value of ab+ bc+ ca-a²-b²- c², when a =2,b=3 and c= (-3)​

Answer 1

Answer:

-31

Step-by-step explanation:

$ab + bc + ca - {a}^{2} - {b}^{2} - {c}^{2}$

so putting values a=2. b=3. and c=(-3). in the equation so we get

$(2)(3) + (3)( - 3) + ( - 3)(2) - {(2)}^{2} - {(3)}^{2} - {( - 3)}^{2}$

$6 - 9 - 6 - 4 - 9 - 9$

$- 31$

Answer 2

Answer:

-31

Step-by-step explanation:

Let's put the value:

(2 X 3) + (3 X -3) + (-3 X 2) - (2)² - (3)² - (-3)²

6 - 9 - 6 - 4 - 9 - 9 (Underlined are getting subtracted)

-9 -4 -9 -9

I can write it like this for clarity : (-9 - 4) + (-9 - 9)

-13 + (-18)

-13 -18

=  -31

Hope it helps