Question

What is the value of ab if (a+b)2=36 (a-b)2=24?​

Answer 1

Answer:

I solve the equation by elimination method..

Step-by-step explanation:

I hope it is clear to you..

Answer 2

The value of (ab) is 2.75.

Step-by-step explanation:

Given that,

$(a+b)^2=36$

$(a+b)=6$.......(1)

And

$(a-b)^2=24$

$(a-b)=2\sqrt6$.......(2)

We need to find the value of ab.

Adding equation (1) and (2) we get :

$(a+b)+(a-b)=6+2\sqrt6$

$2a=6+2\sqrt6\\\\a=\dfrac{6+2\sqrt6}{2}\\\\a=5.5$.........(3)

Put a in equation (1)

$a+b=6\\\\b=6-a\\\\b=6-5.5\\\\b=0.5$......(4)

Now,

$a\times b=5.5\times 0.5\\\\ab=2.75$

So, the value of (ab) is 2.75.

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