Question

what is the value of AB THAT IS || TO DE IN FIGURE​

Answer 1

in the given figure

DE||BC

AD/DB=AE/EC

$\frac{x + 3}{3x + 19} = \frac{x}{3x + 4} \\ (x + 3)(3x + 4) = x(3x + 19) \\ 3 {x}^{2} + 4x + 9x + 12 = 3 {x}^{2} + 19x \\ 3 {x}^{2} + 13x + 12 = 3 {x}^{2} + 19x \\ 12 = 19x - 13x \\ 12 = 6x \\ x = \frac{12}{6} = 2$

AD= x+3

x=2

=2+3=5

DB= 3x+19

x=2

=3(2)+19

=6+19

=25

AE=x=2

EC=3x+4

x=2

=3(2)+4

=6+4

=10

Answer 2

Answer:

DE || BC

:: AD/ DB = AE/ EC

:: x + 3 / 3x + 19 = x / 3x + 4

:: x + 3 ( 3x + 4 ) = x ( 3x + 19 )

:: 3x^2 + 9x + 4x + 12 = 3x^2 + 19x

:: 3x^2 - 3x^2 + 9x +4x + 12 = 19x

:: 9x + 4x + 12 = 19x

:: 13x + 12 = 19x

:: 13x - 19x = - 12

:: -6x = -12

i.e, 6x = 12

:: x = 12/6

:: x = 2

Step-by-step explanation:

The value of x is 2.