what is the value of =ar tr ABC/ar tr PQR
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Step-by-step explanation:
ar(abc)/ar(PQR)=(AB/PQ)^2
(It is a therom area of similar triangles is equal to the square of it proportional sides)
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Ar∆[ABC] divided by Ar∆[PQR]= AB*2÷PQ*2
AB=1. (1)
PQ=3 (2)
So put the value of eq(1) and(2), we get
(1)^2÷(3)^2= 1÷9
Hence prove
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