What is the value of b if y + 3 is a factor of y^3 – 3y^2 + 2y – b Plz answer fast
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Answered by
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Step-by-step explanation:
Y+3 =0
Therefore y =-3
y³– 3y²+ 2y – b =0
(-3)³ - 3(-3)² + 2(-3) -b =0
-27 -27-6 -b =0
-b = 60
Therefore b =-60
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