What is the value of (cos^2 67-sin^2 23)
Answers
Answered by
6
cos²67-sin²23
=cos²67-cos²67
=0
=cos²67-cos²67
=0
ayushmeenadelhi:
Explain bro
properties of complementary angles 90-67=23 got it?
Answered by
11
Heya!
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♦Find the Value of => ( Cos² 67° - Sin²23° )
=> Cos² 67° - [ Sin² ( 90 - 67 ) ]
=> Cos² 67° - Cos²67°
< As Sin ( 90 - Ø ) = Cos Ø >
=> Cos² 67° - Cos² 67°
=> 0
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=======================================================
♦Find the Value of => ( Cos² 67° - Sin²23° )
=> Cos² 67° - [ Sin² ( 90 - 67 ) ]
=> Cos² 67° - Cos²67°
< As Sin ( 90 - Ø ) = Cos Ø >
=> Cos² 67° - Cos² 67°
=> 0
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