what is the value of (cos^267-sin^2 23)
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As 67,23 are complementary angles one will be theta other will be 90-theta
sin theta=cos (90-theta)
sin square theta=cos square (90-theta)
sin square theta - cos square (90-theta)=0
sin square 23- cos square 67 = 0
sin theta=cos (90-theta)
sin square theta=cos square (90-theta)
sin square theta - cos square (90-theta)=0
sin square 23- cos square 67 = 0
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