Math, asked by kondamanideep13, 7 months ago

what is the value of cos(a+b).cos(a-b)​

Answers

Answered by kartikeya327
3

cos(A+B)+cos(A−B)

As we know;

(Cos(A+B)=cosAcosB-sinAsinB

Cos(A-B)=cosAcosB+sinAsinB)

(cosAcosB−sinAsinB)+(cosAcosB+sinAsinB)

CosAcosB-sinAsinB+cosAcosB+sinAsinB

CosAcosB+cosAcosB-sinAsinB+sinAsinB

CosAcosB+cosAcosB+0

2cosAcosB

cos(A+B)+cos(A−B) =2cosAcosB

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Answered by srijabandi123
1

Answer:

How can I simplify cos (A+B) +cos (A-B)?

cos(A+B)+cos(A−B)

As we know;

(Cos(A+B)=cosAcosB-sinAsinB

Cos(A-B)=cosAcosB+sinAsinB)

(cosAcosB−sinAsinB)+(cosAcosB+sinAsinB)

CosAcosB-sinAsinB+cosAcosB+sinAsinB

CosAcosB+cosAcosB-sinAsinB+sinAsinB

CosAcosB+cosAcosB+0

2cosAcosB

cos(A+B)+cos(A−B) =2cosAcosB

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