what is the value of cos(a+b).cos(a-b)
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cos(A+B)+cos(A−B)
As we know;
(Cos(A+B)=cosAcosB-sinAsinB
Cos(A-B)=cosAcosB+sinAsinB)
(cosAcosB−sinAsinB)+(cosAcosB+sinAsinB)
CosAcosB-sinAsinB+cosAcosB+sinAsinB
CosAcosB+cosAcosB-sinAsinB+sinAsinB
CosAcosB+cosAcosB+0
2cosAcosB
cos(A+B)+cos(A−B) =2cosAcosB
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Answer:
How can I simplify cos (A+B) +cos (A-B)?
cos(A+B)+cos(A−B)
As we know;
(Cos(A+B)=cosAcosB-sinAsinB
Cos(A-B)=cosAcosB+sinAsinB)
(cosAcosB−sinAsinB)+(cosAcosB+sinAsinB)
CosAcosB-sinAsinB+cosAcosB+sinAsinB
CosAcosB+cosAcosB-sinAsinB+sinAsinB
CosAcosB+cosAcosB+0
2cosAcosB
cos(A+B)+cos(A−B) =2cosAcosB
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