What is the value of cos(n-1)π. and cos(n+1)π need detailed explanation.
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cos(n+1)π is a function of n. It doesn't have a fixed “value”. The output is determined by the input. For example, if we let n=0.3841 radians, then (cos(0.3841+1))*π = (cos(1.3841))*π = (0.18561)*(3.14159) = 0.58312 (roughly).
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Answer:
cos(n+1)π is a function of n. It doesn't have a fixed “value”. The output is determined by the input. For example, if we let n=0.3841 radians, then (cos(0.3841+1))*π = (cos(1.3841))*π = (0.18561)*(3.14159) = 0.58312 (roughly).
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