Question

what is the value of cos square 67 degree minus sin square 23 degree

Answer 1

cos^267-sin^23
cos^2(90-23)-sin^23
sin^2 23-sin^2 23(cos^2 (90-A)=sinA)
0
Hope it hlps.u.

Answer 2

To find:

Cos^2 67 -  Sin^2 23

Solution:

By formula,

Cos^2A - Sin^2B = Cos ( A + B ) * Cos ( A - B )

Here,

A = 67

B = 23  

Substituting,

We get,

Cos (67 + 23 ) * Cos( 67 - 23 )

Cos ( 90 ) * cos ( 45  )

Substituting values,

0 * 1/√2 .

Hence, Cos^2 67 -  Sin^2 23 = 0

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