what is the value of cos square 67-sin square13
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paryan659:
thanks for answer
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I think your question is cos^2 67°- sin^2 23°
cos square 67°-sin square 23°
=cos square 67°- cos square (90°-23°)
=cos square 67°-cos square67°=0
Therefore the value is 0.
cos square 67°-sin square 23°
=cos square 67°- cos square (90°-23°)
=cos square 67°-cos square67°=0
Therefore the value is 0.
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