What is the value of (cos square 67°- din square 23°)?
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Answered by
0
sin^2(23)=cos^(90-23)=cos^2(67)
Hence.
.both gets cancelled
Answered by
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The answer is
=Cos^2 67° - Sin^2 23°
(sinA = cos(90-A))
(sin23°=sin(90°-23°))
=Cos^2 67° - Cos^2 67°
=0
Hope this helps
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=Cos^2 67° - Sin^2 23°
(sinA = cos(90-A))
(sin23°=sin(90°-23°))
=Cos^2 67° - Cos^2 67°
=0
Hope this helps
Mark as Brainlist
akshatkhurania:
mark as Brainlist
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