Math, asked by subramanyamt1220, 1 year ago

What is the value of (cos square 67°- din square 23°)?

Answers

Answered by bswagatam04
0

\boxed{Answer-0}

sin^2(23)=cos^(90-23)=cos^2(67)

Hence.

.both gets cancelled

Answered by akshatkhurania
0
The answer is
=Cos^2 67° - Sin^2 23°

(sinA = cos(90-A))

(sin23°=sin(90°-23°))

=Cos^2 67° - Cos^2 67°

=0
Hope this helps
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