what is the value of cos square 67degree - sin square 23 degree
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Answered by
2
cos ² 67 ° - sin ² 23°
= cos ² 67° - ( sin 23°)²
= cos² 67° - [ cos ( 90 - 23)° ]²
since sin ∅ = cos ( 90 - ∅ )
∴ cos ² 67° - ( cos 67° )²
= cos ² 67° - cos² 67°
= 0
Hope this helps you !!
# Dhruvsh
= cos ² 67° - ( sin 23°)²
= cos² 67° - [ cos ( 90 - 23)° ]²
since sin ∅ = cos ( 90 - ∅ )
∴ cos ² 67° - ( cos 67° )²
= cos ² 67° - cos² 67°
= 0
Hope this helps you !!
# Dhruvsh
Answered by
1
Cos^2 67°-Sin^2 23°
=Sin^2{90°-23°} - sin^2 23°
=Sin^2 23° -sin^2 23°
=0
=Sin^2{90°-23°} - sin^2 23°
=Sin^2 23° -sin^2 23°
=0
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