Question

what is the value of cos theta + tan theta​

Answer 1

Answer:

$\frac{cos^{2}x +  sinx }{tanx}$ or $\frac{1-sin^{2}x +sinx}{cosx}$

Step-by-step explanation:

cos theta + tan theta

= cos theta + $\frac{sin theta}{cos theta}$

=$\frac{cos^{2}x +  sinx }{tanx}$

that answer would be enough but we also know that

$cos^{2}x$ = 1-$sin^{2}x$

so the final answer is

$\frac{1-sin^{2}x +sinx}{cosx}$