what is the value of cos(x+120)
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Hey !!!
cos(A+B ) = cosA×cosB - sinA×sinB using this formula
cos(x+120° ) = cosx×cos120° - sinx×sin(120°)
=> cosx×cos(90°+30°) - sinx sin(90°+30°)
=> cosx(-cos30°) - sinx cos30°
=> -√3/2cosx - √3/2sinx [•°•cos30° =√3/2]
=> -√3/2 ( cosx + sinx) Answer
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
Hope it helps you !!!
@Rajukumar111
cos(A+B ) = cosA×cosB - sinA×sinB using this formula
cos(x+120° ) = cosx×cos120° - sinx×sin(120°)
=> cosx×cos(90°+30°) - sinx sin(90°+30°)
=> cosx(-cos30°) - sinx cos30°
=> -√3/2cosx - √3/2sinx [•°•cos30° =√3/2]
=> -√3/2 ( cosx + sinx) Answer
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
Hope it helps you !!!
@Rajukumar111
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