what is the value of (cos2 67-Sin2 23
Anonymous:
the answer is 0.
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Answered by
10
HEY HERE'S YOUR ANSWER ⬇️⬇️⬇️⬇️⬇️⬇️
By complementary angles rule of T ratio….
Cos² 67° = sin² ( 90° - 67°) = sin² 23°
So, cos² 67° - sin² 23°
= sin² 23° - sin² 23°
= 0
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By complementary angles rule of T ratio….
Cos² 67° = sin² ( 90° - 67°) = sin² 23°
So, cos² 67° - sin² 23°
= sin² 23° - sin² 23°
= 0
HOPE IT HELPS!!!!
And plz mark it as brainliest
Answered by
55
Hello
Your answer is
____________________________
SOLUTION–
___________
cos²67 – sin²23
as we know that
cos( 90 –θ) = sinθ
Now,
cos²67 – sin²23
—› cos²( 90 – 23 ) – sin²23
—› sin²23 – sin²23
—› 0
So, The value of cos²67 – sin²23 is 0
____________________________
Thanks☺️✌️
Your answer is
____________________________
SOLUTION–
___________
cos²67 – sin²23
as we know that
cos( 90 –θ) = sinθ
Now,
cos²67 – sin²23
—› cos²( 90 – 23 ) – sin²23
—› sin²23 – sin²23
—› 0
So, The value of cos²67 – sin²23 is 0
____________________________
Thanks☺️✌️
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