What is the value of cot 70° + 4 cos 70° ?
(a) 1/✓3
(b) ✓3
Answers
Answered by
0
hi friend here is ur answer hope this will help you.
LHS=cot700+4cos700LHS=cot700+4cos700
=cos700+4cos700sin700sin700=cos700+4cos700sin700sin700
=cos700+2sin1400sin700=cos700+2sin1400sin700
=cos700+2sin400sin700=cos700+2sin400sin700
=cos700+2cos500sin700=cos700+2cos500sin700
=cos700+cos500+cos500sin700=cos700+cos500+cos500sin700
=2cos600cos100+cos500sin700=2cos600cos100+cos500sin700
=cos100+cos500sin700=cos100+cos500sin700
=2cos300cos200sin700=2cos300cos200sin700
=2cos300sin700sin700=2cos300sin700sin700
=2cos300=2cos300
=3–√
LHS=cot700+4cos700LHS=cot700+4cos700
=cos700+4cos700sin700sin700=cos700+4cos700sin700sin700
=cos700+2sin1400sin700=cos700+2sin1400sin700
=cos700+2sin400sin700=cos700+2sin400sin700
=cos700+2cos500sin700=cos700+2cos500sin700
=cos700+cos500+cos500sin700=cos700+cos500+cos500sin700
=2cos600cos100+cos500sin700=2cos600cos100+cos500sin700
=cos100+cos500sin700=cos100+cos500sin700
=2cos300cos200sin700=2cos300cos200sin700
=2cos300sin700sin700=2cos300sin700sin700
=2cos300=2cos300
=3–√
Answered by
9
Hey
Here is your answer,
To find : cot 70° + 4 cos 70°
Solution :
L.H.S= cos 70/sin 70+4 cos 70
= cos 70+4 cos 70 sin 70/sin 70
=cos 70+2 sin 40/sin 70
= cos 70+2 cos 50/sin 70
= cos 70+cos 50+cos 50/sin 70
= 2 cos 60 cos 10+cos 50/sin 70
= cos 10+cos 50/sin 70
= 2 cos 30 cos 20 /cos 20
= root 3
Hope it helps you!
Here is your answer,
To find : cot 70° + 4 cos 70°
Solution :
L.H.S= cos 70/sin 70+4 cos 70
= cos 70+4 cos 70 sin 70/sin 70
=cos 70+2 sin 40/sin 70
= cos 70+2 cos 50/sin 70
= cos 70+cos 50+cos 50/sin 70
= 2 cos 60 cos 10+cos 50/sin 70
= cos 10+cos 50/sin 70
= 2 cos 30 cos 20 /cos 20
= root 3
Hope it helps you!
Dee2611:
how did u get tht 3rd step
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