Question

what is the value of cot(A+B)?

Answer 1

Answer:

hey mate your answer is:-

.

.

Cot(A+B) = (CotACotB-1)/( CotB+CotA).

.

.

hope helpful

mark as brainliest

follow me

Answer 2

Answer:

We know, tan (A + B) = ((tan A) + (tan B)) / (1 - (tan A) *(tan B))

Now, cot (A + B) is just it's inverse.

So, cot (A + B) = (1 - (tan A)*(tan B)) / ((tan A) + (tan B))

Now, multiplying both numerator and denominator by ((cot A)*(cot B)), we get:

cot (A + B) = ((cot A)*(cot B) - 1) / ((cot A) + (cot B)).