What is the value of cot2ø+tanø=?
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Answer:
Given:
- tanA+cotA=2
- tanA+(1/tanA)=2. (cotA=1/tanA)
- (tanA)^2 + 1 =2tanA
- (tanA)^2 - 2tanA + 1 = 0
- (tanA - 1)^2 = 0.
- so tanA=1
- if tanA=1, then cotA=1
- now according to question;
- tan^7(A) +cot^7(A)=?
- (1)^7 + (1)^7=2
- hence, tan^7(A) +cot^7(A)=2
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